document.write( "Question 1207163: two circles intersect (a nd b) and share a common chord (cd). the radius of circle a is 10in, radius circle b = 16 in. distance between centers, 22 in. find cd. \n" ); document.write( "
Algebra.Com's Answer #844877 by ikleyn(52946)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "two circles intersect (A nd B) and share a common chord (CD).
\n" ); document.write( "the radius of circle a is 10in, radius circle b = 16 in. distance between centers, 22 in.
\n" ); document.write( "find cd.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Draw the radii of the circles from their centers to the intersection point C.\r\n" );
document.write( "Connect the centers by the straight line AB.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "You will get a triangle ABC with the sides 10 in, 16 in and 22 in.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Find its area using the Heron's formula\r\n" );
document.write( "\r\n" );
document.write( "    area = \"sqrt%28s%2A%28s-10%29%2A%28s-16%29%2A%28s-22%29%29\",\r\n" );
document.write( "\r\n" );
document.write( "where s = \"%2810%2B16%2B22%29%2F2%29\" = 24 is the semi-perimeter.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Substituting this number into the formula, you will get\r\n" );
document.write( "\r\n" );
document.write( "    area = \"sqrt%2824%2A%2824-10%29%2A%2824-16%29%2A%2824-22%29%29\" = \"sqrt%2824%2A14%2A8%2A2%29\" = \"sqrt%283%2A8%5E2%2A7%2A4%29\" = \r\n" );
document.write( "\r\n" );
document.write( "         = \"8%2A2%2Asqrt%2821%29\" = \"16%2Asqrt%2821%29\" = 73.32121112... square inches.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Write the formula for the area of triangle ABC in other way, using the base AB = 22 in and the height h\r\n" );
document.write( "from point C to the base\r\n" );
document.write( "\r\n" );
document.write( "    area = \"%281%2F2%29%2A22%2Ah\" = 11*h  square inches.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "You will get an equation\r\n" );
document.write( "\r\n" );
document.write( "    11*h = \"16%2Asqrt%2821%29\".\r\n" );
document.write( "\r\n" );
document.write( "Hence,  \r\n" );
document.write( "\r\n" );
document.write( "    h = \"%2816%2F11%29%2Asqrt%2821%29%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "This value of h is half of the length CD;  so\r\n" );
document.write( "\r\n" );
document.write( "    CD = \"%2832%2F11%29%2Asqrt%2821%29\" = 13.331 inches  (rounded).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "At this point, the problem is just solved.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The length CD is  \"%2832%2F11%29%2Asqrt%2821%29\" = 13.331 inches  (rounded).\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );