document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207157>Question 1207157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A two digit number is such that the sum of the digits is 12 if the digits are interchanged the value of the new number formed is15 more than twice the value of the original number find the original number  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844868 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A two digit number is such that the sum of the digits is 12 if the digits are interchanged the value of the new number formed is15 more than twice the value of the original number find the original number\r<BR>\n" );
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document.write( "Let ten's digit be x<BR>\n" );
document.write( "and the units digit be y\r<BR>\n" );
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document.write( "the sum of the digits is 12<BR>\n" );
document.write( "x+y=12..............................1\r<BR>\n" );
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document.write( "if the digits are interchanged the value of the new number formed is15 more than twice the value of the original number<BR>\n" );
document.write( "Value of original number = 10x+Y\r<BR>\n" );
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document.write( "Reverse number will be 10y+x\r<BR>\n" );
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document.write( "10y+x = 15+2(10x+y)\r<BR>\n" );
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document.write( "10y+x = 15+20x+2y\r<BR>\n" );
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document.write( "rearrange\r<BR>\n" );
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document.write( "10y-2y +x-20x = 15\r<BR>\n" );
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document.write( "8y-19x  = 15.......................2\r<BR>\n" );
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document.write( "solve 1 & 2\r<BR>\n" );
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document.write( "Multiply (1) by -8\r<BR>\n" );
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document.write( "-8x-8y= -96..................3<BR>\n" );
document.write( "add (1) &(3)<BR>\n" );
document.write( "-27x = -81\r<BR>\n" );
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document.write( "x = 3\r<BR>\n" );
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document.write( "now x+y =12\r<BR>\n" );
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document.write( "so y = 12-3 = 9\r<BR>\n" );
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document.write( "So the number is 39\r<BR>\n" );
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document.write( "check\r<BR>\n" );
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document.write( "93 = 15+2(39)\r<BR>\n" );
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document.write( "93 = 15+ 78=93\r<BR>\n" );
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document.write( "LHS = RHS\r<BR>\n" );
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document.write( " </SPAN>\n" );
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