document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207010>Question 1207010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves Orlando at 4:00 PM.  A second train leaves the same city in the same direction at 8:00 PM.  The second train travels 112mph<BR>\n" );
document.write( " faster than the first.  If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844803 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "When the second train overtakes the first, the first train has been traveling for 6 hours and the second train for 2 hours.<br><BR>\n" );
document.write( "The ratio of times is 3:1, and the distances are the same, so the ratio of speeds is 3:1.<br><BR>\n" );
document.write( "Let x = speed of first train<BR>\n" );
document.write( "Then 3x = speed of second train<br><BR>\n" );
document.write( "The difference in their speeds is 112mph:<br><BR>\n" );
document.write( "3x-x=112<BR>\n" );
document.write( "2x=112<BR>\n" );
document.write( "x=56<br><BR>\n" );
document.write( "ANSWERS: The speeds of the two trains are<br><BR>\n" );
document.write( "first train: x = 56mph<BR>\n" );
document.write( "second train: 3x - 168mph<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );