document.write( "Question 1207010: A train leaves Orlando at 4:00 PM. A second train leaves the same city in the same direction at 8:00 PM. The second train travels 112mph
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Algebra.Com's Answer #844802 by mccravyedwin(406) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "10 PM is 6 hours after 4 PM and 2 hours after 8 PM\r\n" );
document.write( "1st train's speed is r mph\r\n" );
document.write( "2nd train's speed is r+112 mph\r\n" );
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document.write( "Make a chart:\r\n" );
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document.write( "                   |rate |time |distance|\r\n" );
document.write( "1st train at 10 PM |  r  |  6  |   6r   |\r\n" );
document.write( "2nd train at 10 PM |r+112|  2  |2(r+112)|\r\n" );
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document.write( "Set the distances equal.\r\n" );
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document.write( "Solve that for r and you'll get r = 56 mph for the 1st train.\r\n" );
document.write( "Add 112 to 56 and you'll get 168 mph for the 2nd train.\r\n" );
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document.write( "Can a train go that fast?  Could it stay on the rails? LOL  \r\n" );
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document.write( "Edwin

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