document.write( "Question 1206997: A truck starts from Amsterdam at 10 am and heads for Prague, 875 km away. At the same time, a car leaves Prague and heads for Amsterdam at 100 kph. If the vehicles meet at 3 pm, what is the truck's speed? \n" ); document.write( "
Algebra.Com's Answer #844800 by josgarithmetic(39625)\"\" \"About 
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document.write( "                           SPEEDS          TIME        DISTANCES, km\r\n" );
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document.write( "TRUCK (Amstrd.to.Prag)                       5              \r\n" );
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document.write( "CAR (Prag.to.Amstrd.)         100            5         100*5=500\r\n" );
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document.write( "TOTAL CONSUMED                                             875\r\n" );
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document.write( "                           SPEEDS          TIME        DISTANCES, km\r\n" );
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document.write( "TRUCK (Amstrd.to.Prag)     375/5             5        875-500=375      \r\n" );
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document.write( "CAR (Prag.to.Amstrd.)         100            5         100*5=500\r\n" );
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document.write( "TOTAL CONSUMED                                             875\r\n" );
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\n" ); document.write( "Speed of the truck, \"375%2F5=highlight%2875%29\" kph\r
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\n" ); document.write( "When they \"meet\", time passed was 5 hours and total distance traveled for both was sum of 875+100=975 km, but this sum distance not needed. Both car and truck meet at same place.\r
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\n" ); document.write( "\n" ); document.write( "TRUCK'S SPEED:\r
\n" ); document.write( "\n" ); document.write( "\"cross%28875%2F5=175%29\" kilometers per hour\r
\n" ); document.write( "\n" ); document.write( "MAJOR MISTAKE, took, \"...heads for Amsterdam at 100 kph\" as '100 km'. \n" ); document.write( "
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