document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116170>Question 116170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you are dealt two cards successively (with replacement of the first) from a standard deck, find the probability of getting a heart on the first card and a diamond on the second? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84480 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 52 cards<BR>\n" );
document.write( "13 hearts, 13 diamonds, 13 spades, 13 clubs<BR>\n" );
document.write( "P(Heart) = 13/52. <BR>\n" );
document.write( "You replace the card<BR>\n" );
document.write( "P(Diamond) = 13/52. <BR>\n" );
document.write( "Independent events, multiply the probabilities.<BR>\n" );
document.write( "P(Heart then Diamond) = 13/52*13/52 = 1/4*1/4 = 1/16 </SPAN>\n" );
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