document.write( "Question 1206997: A truck starts from Amsterdam at 10 am and heads for Prague, 875 km away. At the same time, a car leaves Prague and heads for Amsterdam at 100 kph. If the vehicles meet at 3 pm, what is the truck's speed? \n" ); document.write( "

Algebra.Com's Answer #844792 by Theo(13342) $\"\"$ $\"About$

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the distance between amsterdam and prague is 875 kilometers.
\n" ); document.write( "the truck leave amsterdam at 10:00 am.
\n" ); document.write( "at the same time, the car leaves prague, heading for amsterdam.
\n" ); document.write( "they meet at 3:00 pm.\r
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\n" ); document.write( "\n" ); document.write( "if they meet at 3:00 pm, then they both must have been traveling for 5 hours.
\n" ); document.write( "the care will have been traveling 5 * 100 = 500 kilometers.
\n" ); document.write( "this means the truck must have been traveling for 875 - 500 = 375 kilometers.\r
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\n" ); document.write( "\n" ); document.write( "since the truck was also traveling for 5 yours, then the speed of the truck must have been 375 / 5 = 75 kilometers per hour.\r
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\n" ); document.write( "\n" ); document.write( "since rate * time = distance, .....\r
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\n" ); document.write( "\n" ); document.write( "the formula for the truck was R * 5 = 875 - D
\n" ); document.write( "the formula for the car was 100 * 5 = D\r
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\n" ); document.write( "\n" ); document.write( "in the second equation, we solved for D to get D = 500.
\n" ); document.write( "in the first equation we solved for 875 - D to get 375.
\n" ); document.write( "once we got 875 - D, we could then solve for R to get R = 75.\r
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