document.write( "Question 116162This question is from textbook
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document.write( ": Joe has a collection of nickels and dimes that is worth $6.00. If the number of dimes were doubled and the number of nickels were increased by 6, the value of the coins would be $9.90. How many dimes does he have? \n" );
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Algebra.Com's Answer #84479 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Joe has a collection of nickels and dimes that is worth $6.00. If the number of dimes were doubled and the number of nickels were increased by 6, the value of the coins would be $9.90. How many dimes does he have? \n" ); document.write( ": \n" ); document.write( "Using the 1st statement we can write an equation: \n" ); document.write( ".05n + .10d = 6.00 \n" ); document.write( "Rearrange so we can use for substitution \n" ); document.write( ".05n = 6 - .10d \n" ); document.write( ": \n" ); document.write( "Multiply equation by 20 to make the coefficient of n = 1: \n" ); document.write( "1n = (120 - 2d) \n" ); document.write( ": \n" ); document.write( "Using the 2nd statement, write another equation: \n" ); document.write( "\"If the number of dimes were doubled and the number of nickels were increased by 6, the value of the coins would be $9.90.\" \n" ); document.write( ": \n" ); document.write( ".05(n+6) + 2(.10d) = 9.90 \n" ); document.write( ".05n + .3 + .20d = 9.90 \n" ); document.write( ".05n + .2d = 9.9 - .3 \n" ); document.write( ".05n + .2d = 9.6 \n" ); document.write( ": \n" ); document.write( " How many dimes does he have? \n" ); document.write( "Substitute (120-2d) for n in the above equation: \n" ); document.write( ".05(120-2d) + .2d = 9.6 \n" ); document.write( " 6 - .10d + .2d = 9.6 \n" ); document.write( "-.1d + .2d = 9.6 - 6 \n" ); document.write( "+.1d = 3.6 \n" ); document.write( "d = 3.6/.1 \n" ); document.write( "d = 36 dimes in the collection \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "To confirm our solution we need to find out how many nickels: \n" ); document.write( "n = 120 - 2(36) \n" ); document.write( "n = 120 - 72 \n" ); document.write( "n = 48 dimes \n" ); document.write( ": \n" ); document.write( "Check solution using the 1st statement: \n" ); document.write( "\"Joe has a collection of nickels and dimes that is worth $6.00.\" \n" ); document.write( ".05(48) + .10(36) = \n" ); document.write( "2.40 + 3.60 = $6 \n" ); document.write( ": \n" ); document.write( "You can check the solutions using the statement: \n" ); document.write( "\"If the number of dimes were doubled and the number of nickels were increased by 6, the value of the coins would be $9.90.\" \n" ); document.write( " |