document.write( "Question 1206993: How many different committees can be formed from 6 teachers and 39 students if the committee consist of 3 teachers and 3 students?
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Algebra.Com's Answer #844780 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "In this case, we need to form a committee of $\"6+\"$ members consisting of $\"3\"$ teachers and $\"3\"$ students from a total of $\"6+\"$ teachers and $\"39+\"$ students. \r
\n" ); document.write( "\n" ); document.write( "The number of ways to select $\"3\"$ teachers from $\"6+\"$ is denoted as $\"C%286%2C3%29\"$ and the number of ways to select $\"3\"$ students from $\"39+\"$ is denoted as $\"C%2839%2C3%29\"$ . \r
\n" ); document.write( "\n" ); document.write( "The total number of ways to form the committee is the product of these two combinations, which is \r
\n" ); document.write( "\n" ); document.write( " $\"C%286%2C3%29%2AC%2839%2C3%29+=+20%2A9139+=+182780\"$ \r
\n" ); document.write( "\n" ); document.write( "Therefore, there are $\"182780\"$ different ways to form the committee.\r
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