document.write( "Question 1196122: A particle moving in a straight line has initial velocity of 2 m/s at a point O on the line. The particle moves so that its acceleration is t seconds later is given by (2t-6) meter per second squared. Find the (a) Velocity when t= 5 seconds (b) Displacement of the particle in the fifth seconds. \n" ); document.write( "
Algebra.Com's Answer #844775 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "        In the post by tutor @Shin, the answer to question  (a)  is correct,
\n" ); document.write( "        while the answer to question  (b)  is  INCORRECT.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "The correct answer to question (b) is\r\n" );
document.write( "\r\n" );
document.write( "    the displacement of the particle in the fifth second is s(5) - s(4), \r\n" );
document.write( "\r\n" );
document.write( "    where  s(t) = \"t%5E3%2F3\" - \"3t%5E2\" + 2t.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So,  s(4) = \"4%5E3%2F3\" - \"3%2A4%5E2\" + 2*4 = -18.6667 m   (rounded),\r\n" );
document.write( "\r\n" );
document.write( "     s(5) = \"5%5E3%2F3\" - \"3%2A5%5E2\" + 2*5 = -23.3333 m   (rounded),\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "and the displacement in the fifth second is\r\n" );
document.write( "\r\n" );
document.write( "     s(5) - s(4) =  -23.3333 - (-18.6667) = -4.6666 m  (rounded).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER to (b)  is  -4.6667 m  (rounded).\r\n" );
document.write( "
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );