document.write( "Question 1206989: A container with full capacity of 1l of water started leaking at a rate of 5 ml per second. At this rate, what fraction of the tank will still be filled with water after 2 minutes? Give your answer in the simplest form.\r
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document.write( "(1) 2/5\r
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document.write( "(2) 3/10\r
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document.write( "(3) 2/3\r
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document.write( "(4) 3/5 \n" );
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Algebra.Com's Answer #844771 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 2/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The \"1 l\" looks a lot like two lowercase L's put together. \n" ); document.write( "Perhaps your teacher should have written it as \"1 L\" or \"one liter\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of seconds that elapse \n" ); document.write( "y = amount of water, in mL, in the tank\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is \n" ); document.write( "y = -5x+1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is because the equation is of y = mx+b form \n" ); document.write( "m = -5 = slope = how much water in mL leaks per second \n" ); document.write( "b = 1000 = starting number of mL of water \n" ); document.write( "1000 mL = 1 liter\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we plugged x = 0 into y = -5x+1000, then we'd get y = 1000.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug x = 120 into the equation to find that y = -5*(120)+1000 = 400\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At the 2 minute marker, aka 120 seconds, 400 mL of water remains. \n" ); document.write( "400/1000 = 2/5 of the tank is full by this point.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another approach\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 liter = 1000 mL \n" ); document.write( "1 mL = 1/1000 = 0.001 liter \n" ); document.write( "1 mL = 0.001 liter \n" ); document.write( "5*1 mL = 5*0.001 liter \n" ); document.write( "5 mL = 0.005 liter\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The tank is losing 0.005 liters of water per second. \n" ); document.write( "After 120 seconds (aka 2 minutes), the tank lost 120*0.005 = 0.6 liters of water. \n" ); document.write( "The amount remaining is 1 liter - 0.6 liters = 0.4 liters \n" ); document.write( "Divide this over the tank's capacity of 1 liter to get 0.4, note the \"liters\" units cancel when dividing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then convert that to a fraction \n" ); document.write( "0.4 = 4/10 = 2/5 \n" ); document.write( " \n" ); document.write( " |