document.write( "Question 116106: With the current, a motorboat travels 60 mi in 3 h. Against the current, it takes 2 h longer to travel 60 mi. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #84473 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 60/3=20 MPH WITH THE CURRENT. \n" ); document.write( "60/5=12 MPH. \n" ); document.write( "SO THE SPEED=20-X & 12+X \n" ); document.write( "20-X=12+X \n" ); document.write( "-X-X=12-20 \n" ); document.write( "-2X=-8 \n" ); document.write( "X=-8/-2 \n" ); document.write( "X=4 MPH IS THE CURRENT. \n" ); document.write( " \n" ); document.write( " |