document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1206958>Question 1206958</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ways can a committee of 6 people from a group of 10 people be chosen along with a committee president and a secretary? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844706 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "There are 10 choices for the president and 9 choices for the secretary; that makes 10*9=90 ways to choose those two officers.<br><BR>\n" );
document.write( "After that, there are 8 people to choose from, of which 6 are to be chosen.  The number of ways of doing that is C(8,6) = C(8,2) = 28.<br><BR>\n" );
document.write( "The wording of the problem allows different interpretations.<br><BR>\n" );
document.write( "If the intent of the question is how many ways the committee can be chosen after the president and secretary have been chosen, then the answer is 28.<br><BR>\n" );
document.write( "ANSWER #1: 28<br><BR>\n" );
document.write( "If the intent of the question is how many ways the president, secretary, and committee of 6 can be chosen, then the answer is 90*28=2520.<br><BR>\n" );
document.write( "ANSWER #2: 2520<br>\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );