document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1206928>Question 1206928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sketch a figure and solve each right triangle ABC with right angle at C. given that:<BR>\n" );
document.write( "1. A = 15° and c = 37<BR>\n" );
document.write( "2. B = 64° and c = 19.2<BR>\n" );
document.write( "3. A = 15° and c = 25<BR>\n" );
document.write( "4. A = 45° and c = 16<BR>\n" );
document.write( "5. B = 56° and c = 16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844695 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "The Law of Sines is a bit overkill, but it is a method you could follow.\r<BR>\n" );
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document.write( "A more easier approach would be to use the SOH-CAH-TOA trig ratios<ul><li>SOH = sine opposite hypotenuse</li><li>CAH = cosine adjacent hypotenuse</li><li>TOA = tangent opposite adjacent</li></ul>I'll focus on problem 1 only and leave the others for the student.\r<BR>\n" );
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document.write( "C = 90 degrees<BR>\n" );
document.write( "A = 15 degrees<BR>\n" );
document.write( "B = 90-A = 90-15 = 75 degrees<BR>\n" );
document.write( "Angles A and B are complementary, i.e. they add to 90 degrees, since we're dealing with a right triangle.\r<BR>\n" );
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document.write( "Now that we know the angles, we can determine the side lengths.<BR>\n" );
document.write( "sin(angle) = opposite/hypotenuse<BR>\n" );
document.write( "sin(A) = a/c<BR>\n" );
document.write( "sin(15) = a/37<BR>\n" );
document.write( "a = 37*sin(15)<BR>\n" );
document.write( "a = 9.576305 approximately<BR>\n" );
document.write( "Please make sure that your calculator is set to degrees mode. <BR>\n" );
document.write( "I often check by typing in something like \"sin(30)\" and the output for this example should be 0.5\r<BR>\n" );
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document.write( "And,<BR>\n" );
document.write( "sin(angle) = opposite/hypotenuse<BR>\n" );
document.write( "sin(B) = b/c<BR>\n" );
document.write( "sin(75) = b/37<BR>\n" );
document.write( "b = 37*sin(75)<BR>\n" );
document.write( "b = 35.739256 approximately\r<BR>\n" );
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document.write( "Here is the fully solved triangle for problem 1<BR>\n" );
document.write( "Angles: A = 15, B = 75, C = 90<BR>\n" );
document.write( "Sides: a = 9.576305 approximately, b = 35.739256 approximately, c = 37<BR>\n" );
document.write( "Round the approximate values however needed.\r<BR>\n" );
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document.write( "I'll leave the sketch for the student to do, as well as problems 2 through 5.\r<BR>\n" );
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document.write( "More practice found here<BR>\n" );
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