document.write( "Question 1206947: y=3x-2. Graph this linear equation when slope is 3 and intercept y is (0, -2)
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Algebra.Com's Answer #844685 by Theo(13342)\"\" \"About 
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you want to graph y = 3x - 2.
\n" ); document.write( "your slope is 3 and your y-intercept is -2, based on the equation.
\n" ); document.write( "here's the graph that i got using desmos.com/calculator.\r
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\n" ); document.write( "\n" ); document.write( "your equation is y = 3x - 2
\n" ); document.write( "the slope is 3.
\n" ); document.write( "the y-intercept is -2.
\n" ); document.write( "the y-intercept is at (0,-2)\r
\n" ); document.write( "\n" ); document.write( "the x-intercept is the value of x when y is 0.
\n" ); document.write( "the equation of y = 3x - 2 becomes 0 = 3x - 2
\n" ); document.write( "solve for x to get x = 2/3.
\n" ); document.write( "the x-intercept is at (2/3,0)\r
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\n" ); document.write( "\n" ); document.write( "we have confirmed that the y-intercept is -2 and the x-intercept is 2/3.\r
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\n" ); document.write( "\n" ); document.write( "the slope is (y2-y1)/(x2-x1).
\n" ); document.write( "when (x1,y1) = (0,-2) and (x2,y2) = (2/3,0), the slope becomes:
\n" ); document.write( "(0--2) / (2/3 - 0) which becomes 2/(2/3) which becomes 2*3/2 which becomes 3.
\n" ); document.write( "the slope is 3.\r
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\n" ); document.write( "\n" ); document.write( "let me know if you have any questions.
\n" ); document.write( "theo\r
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