document.write( "Question 1206917: Test the given claim. Assume that a simple random sample is selected from a normally distributed population. Use either the​ P-value method or the traditional method of testing hypotheses.
\n" ); document.write( "Company A uses a new production method to manufacture aircraft altimeters. A simple random sample of new altimeters resulted in errors listed below. Use a 0.05 level of significance to test the claim that the new production method has errors with a standard deviation greater than 32.2​ ft, which was the standard deviation for the old production method. If it appears that the standard deviation is​ greater, does the new production method appear to be better or worse than the old​ method? Should the company take any​ action?
\n" ); document.write( "-45​, 76​, -21​, -75​, -43​, 11​, 15​, 52​, -5​, -54​, -108​, -108
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Algebra.Com's Answer #844646 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "sigma = \"sigma\" = population standard deviation
\n" ); document.write( "s = sample standard deviation\r
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\n" ); document.write( "\n" ); document.write( "It is easy to compute variable \"s\" because we have the sample of values given to us, and a calculator makes quick work of this computation.
\n" ); document.write( "When using a calculator you should get s = 58.218176 approximately.\r
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\n" ); document.write( "\n" ); document.write( "On the other hand, determining sigma is much more costly.
\n" ); document.write( "This is because we need to take a census of a large population.
\n" ); document.write( "This is true of many population parameters which is why statistics is needed.
\n" ); document.write( "The idea is that variable \"s\" will estimate sigma.\r
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\n" ); document.write( "\n" ); document.write( "The goal is to see if sigma = 32.2 or sigma > 32.2\r
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\n" ); document.write( "\n" ); document.write( "Null Hypothesis: sigma = 32.2
\n" ); document.write( "Alternate Hypothesis: sigma > 32.2\r
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\n" ); document.write( "\n" ); document.write( "Some textbooks will replace the \"equals\" with \"less than or equal to\", but I want to be very narrow on what the null focuses on. The null should focus on one value only. \r
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\n" ); document.write( "\n" ); document.write( "The \"greater than\" in the alternative hypothesis indicates we have a right-tailed test. \r
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\n" ); document.write( "\n" ); document.write( "Since we're doing a hypothesis test on sigma, we'll need to do a Chi-Square Test.\r
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\n" ); document.write( "\n" ); document.write( "Chi-Square Test Statistic = (n-1)*(s^2)/(sigma^2)
\n" ); document.write( "= (12-1)*(58.218176^2)/(32.2^2)
\n" ); document.write( "= 35.958 approximately\r
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\n" ); document.write( "\n" ); document.write( "Now use a Chi-Square Table to determine the p-value is less than 0.001
\n" ); document.write( "The sample size n = 12 leads to df = n-1 = 12-1 = 11.
\n" ); document.write( "df = degrees of freedom
\n" ); document.write( "The idea is to look through the df = 11 row and see if you can find the test statistic 35.958
\n" ); document.write( "Unfortunately this value is not in this row but notice it's larger than 31.264 which corresponds to a p-value of 0.001; as the test statistic gets larger, the p-value will get smaller. \r
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\n" ); document.write( "\n" ); document.write( "Since the p-value is smaller than alpha = 0.05, it means we have strong evidence to reject the null.
\n" ); document.write( "Remember: \"If the p-value is low, then the null must go\".\r
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\n" ); document.write( "\n" ); document.write( "Rejecting the null means we conclude that sigma > 32.2 appears to be the case.
\n" ); document.write( "The new method is worse compared to the old method.
\n" ); document.write( "This new production line has more errors in the altimeters and the company should take action to fix this. \r
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\n" ); document.write( "\n" ); document.write( "If you prefer the traditional method over the p-value method, then use a Chi-Square Table to see that the critical value is roughly 19.675 when alpha = 0.05 and df = 11\r
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\n" ); document.write( "\n" ); document.write( "P(chiSquare > 19.675) = 0.05 approximately when df = 11
\n" ); document.write( "The value 19.675 is found in the table unlike earlier when 35.958 wasn't in the table.\r
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\n" ); document.write( "\n" ); document.write( "Chi-Square critical value = 19.675
\n" ); document.write( "Chi-Square test statistic = 35.958\r
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\n" ); document.write( "\n" ); document.write( "We see the test statistic is larger than the critical value, so it's in the rejection region.
\n" ); document.write( "Recall this is a right-tailed test.
\n" ); document.write( "Therefore we reject the null and conclude sigma > 32.2
\n" ); document.write( "The company should take action to fix the issue.
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