document.write( "Question 116161This question is from textbook
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document.write( ": Joe has a collection of nickels and dimes that is worth $6.00. If the number of dimes were doubled and the number of nickels were increased by 6, the value of the coins would be $9.90. How many dimes does he have? \n" );
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Algebra.Com's Answer #84463 by keerthu(5)![]() ![]() ![]() You can put this solution on YOUR website! 0.05n + 0.10d = 6 ----> (1) \n" ); document.write( "0.05(n+6) + 0.10(2d) = 9.90 ----> (2)\r \n" ); document.write( "\n" ); document.write( "equation 2 becomes,\r \n" ); document.write( "\n" ); document.write( "0.05n + 0.20d = 9.60 -----> (3)\r \n" ); document.write( "\n" ); document.write( "solving (1) and (3), we get,\r \n" ); document.write( "\n" ); document.write( "d = 36 and n = 48 where d is the number of dimes and n is the number of nickels. \n" ); document.write( " |