document.write( "Question 1206859: The base of right pyramid ABCDF is
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Algebra.Com's Answer #844615 by mccravyedwin(407)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First find the area of triangle BFK, half of triangle BFD.\r\n" );
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document.write( "BD=10, so BK=5\r\n" );
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document.write( "\"BK%2F%28FK%29=tan%2836%5Eo%29\"\r\n" );
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document.write( "\"5%2F%28FK%29=tan%2836%5Eo%29\"\r\n" );
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document.write( "\"Fk%2Atan%2836%5Eo%29=5\"\r\n" );
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document.write( "\"FK=5%2Ftan%2836%5Eo%29\"\r\n" );
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document.write( "\"matrix%281%2C4%2CAREA%2COF%2CDELTA%2CBFK%29\"\"%22%22=%22%22\"\"expr%281%2F2%29BK%2AFK\"\"%22%22=%22%22\"\"expr%281%2F2%29%2A5%2A%285%2Ftan%2836%5Eo%29%29\"\"%22%22=%22%22\"\"25%2F%282tan%2836%5Eo%29%29\"\r\n" );
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document.write( "\"matrix%281%2C4%2CAREA%2COF%2CDELTA%2CBFD%29\"\"%22%22=%22%22\"\"25%2F%28tan%2836%5Eo%29%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C34.40954801%2Ccm%5E2%29\"\r\n" );
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document.write( "To find the perimeter, we need to find FB.\r\n" );
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document.write( "\"BD%2F%28FB%29=sin%2836%5Eo%29\"\r\n" );
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document.write( "\"5%2F%28FB%29=sin%2836%5Eo%29\"\r\n" );
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document.write( "\"FB%2Asin%2836%5Eo%29=5\"\r\n" );
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document.write( "\"FB=5%2Fsin%2836%5Eo%29=8.506508084=FD\"\r\n" );
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document.write( "\"matrix%281%2C4%2CAREA%2COF%2CDELTA%2CBFD%29\"\"%22%22=%22%22\"\"25%2F%28tan%2836%5Eo%29%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C34.40954801%2Ccm%5E2%29\"\r\n" );
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document.write( "\"matrix%281%2C2%2C34.40954801%2Ccm%5E2%29\"\r\n" );
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document.write( "\"matrix%281%2C4%2CPERIMETER%2COF%2CDELTA%2CBFD%29\"\"%22%22=%22%22\"\"FB%2BBD%2BFD\"\"%22%22=%22%22\"\"8.506508084%2B10%2B8.506508084\"\"%22%22=%22%22\"\"matrix%281%2C2%2C27.01301617%2Ccm%29\".\r\n" );
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document.write( "Rounding off to the nearest integer:\r\n" );
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document.write( "\"matrix%281%2C4%2CAREA%2COF%2CDELTA%2CBFD%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C34%2Ccm%5E2%29\"\r\n" );
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document.write( "\"matrix%281%2C4%2CPERIMETER%2COF%2CDELTA%2CBFD%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C27%2Ccm%29\".\r\n" );
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document.write( "Edwin
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