document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1206862>Question 1206862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 8 minutes, a conveyor belt can move 1,000 bushels of corn into a storage bin. A smaller belt can move 1,000 bushels to the storage bin in 14 minutes. If both belts are used, how long will it take to move 1,000 bushels to the storage bin? </SPAN>\n" );
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document.write( "Answer: <font color=red>5.090909 minutes approximately</font><BR>\n" );
document.write( "The \"09\" decimal portion repeats forever. <BR>\n" );
document.write( "This is equivalent to the mixed number 5 & 1/11 minutes.\r<BR>\n" );
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document.write( "Explanation\r<BR>\n" );
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document.write( "The LCM of 8 and 14 is 56 because:<BR>\n" );
document.write( "8*14/2 = 56<BR>\n" );
document.write( "where the \"divide by 2\" portion is the GCF of 8 and 14.<BR>\n" );
document.write( "LCM = x*y/GCF\r<BR>\n" );
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document.write( "Conveyor A moves 1000 bushels of corn in 8 minutes.<BR>\n" );
document.write( "If it keeps this same rate then it moves 7*1000 = 7000 bushels in 7*8 = 56 minutes.\r<BR>\n" );
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document.write( "Conveyor B moves 1000 bushels of corn in 14 minutes.<BR>\n" );
document.write( "If it keeps this same rate then it moves 4*1000 = 4000 bushels in 4*14 = 56 minutes.\r<BR>\n" );
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document.write( "The key is to get both conveyors moving some amount of corn in the same amount of time.<BR>\n" );
document.write( "Combine those amounts:<BR>\n" );
document.write( "A+B = 7000+4000 = 11000\r<BR>\n" );
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document.write( "11,000 bushels of corn are moved in 56 minutes when the conveyor belts work together.<BR>\n" );
document.write( "This assumes neither conveyor belt hinders the other.<BR>\n" );
document.write( "The combined unit rate would be 11000/56 = 1375/7 = 196.42857 bushels per minute approximately.\r<BR>\n" );
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document.write( "Then,<BR>\n" );
document.write( "rate*time = amountDone<BR>\n" );
document.write( "time = amountDone/rate<BR>\n" );
document.write( "time = (1000 bushels)/( 1375/7 bushels per min)<BR>\n" );
document.write( "time = (1000*7/1375) minutes<BR>\n" );
document.write( "time = (56/11) minutes<BR>\n" );
document.write( "time = 5.090909090909 minutes approximately<BR>\n" );
document.write( "The \"09\" part repeats forever.\r<BR>\n" );
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document.write( "If you want the answer as a mixed number then,<BR>\n" );
document.write( "5.090909090909 = 5 & 1/11<BR>\n" );
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