document.write( "Question 1206865: Assuming the population has an approximate normal distribution, if a sample size
\n" ); document.write( "n=28 has a sample mean x¯=39 with a sample standard deviation s=2, find the margin of error at a 80% confidence level. Round the answer to two decimal places.
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Algebra.Com's Answer #844560 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Margin of error =\"+Z+%2A+%28mu+%2F+sqrt%28n%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Where:\r
\n" ); document.write( "\n" ); document.write( "\"Z\" is \"Z\"-score corresponding to the desired confidence level (for a \"80\"% confidence level, \"Z\"\"1.282\")\r
\n" ); document.write( "\n" ); document.write( "a sample size \"n=28+\"
\n" ); document.write( "a sample mean x¯=\"39\" or \"mu=39\"
\n" ); document.write( "a sample standard deviation \"s=2\"\r
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\n" ); document.write( "\n" ); document.write( "Margin of error = \"1.282+%2A+%2839+%2F+sqrt%2828%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Margin of error =\"+1.282+%2A+%287.37030722367993%29\"\r
\n" ); document.write( "\n" ); document.write( "Margin of error = \"9.45\"\r
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