document.write( "Question 1206856: 1. (I&-E) -> -I |-(Conclusion) I -> E \n" ); document.write( "
Algebra.Com's Answer #844544 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "1. (I&~E) -> ~I |-(Conclusion) I -> E\r\n" ); document.write( " \r\n" ); document.write( " |2. I Assumption for conditional proof\r\n" ); document.write( " |3. ~~I 2, double negation\r\n" ); document.write( " |4. ~(I&~E) 1,3, transposition\r\n" ); document.write( " |5. ~I v ~~E 4, DeMorgan's law\r\n" ); document.write( " |6. ~I v E 5, double negation\r\n" ); document.write( " |7. E 6,3, disjunctive syllogism\r\n" ); document.write( "8. I -> E lines 2-7 for conditional proof.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |