document.write( "Question 1206850: Let z be a standard normal random variable with mean 𝜇 = 0 and standard deviation 𝜎 = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.)
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document.write( "P(z > 1.13) =
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Algebra.Com's Answer #844526 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answer: 0.1292 \n" ); document.write( "This value is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As the instructions mention, turn to the page that has Table 3 in Appendix I. \n" ); document.write( "Locate the row that starts with 1.1 \n" ); document.write( "Locate the column that has 0.03 at the top. \n" ); document.write( "The intersection of this row and column yields the approximate value 0.87076 \n" ); document.write( "It indicates that P(Z < 1.13) = 0.87076 approximately.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For students following along that don't have their stats textbook with them, refer to online resources such as this \n" ); document.write( "https://www.ztable.net/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "P(Z > 1.13) = 1-P(Z < 1.13) \n" ); document.write( "P(Z > 1.13) = 1-0.87076 \n" ); document.write( "P(Z > 1.13) = 0.12924 \n" ); document.write( "P(Z > 1.13) = 0.1292 which is the final answer when rounding to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Verification\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are many ways to verify this with a handheld calculator, an app on your phone, or a website. \n" ); document.write( "Feel free to explore your favorite method. \n" ); document.write( "It's probably best to use a tool that is approved by your teacher for exam settings. \n" ); document.write( "Once you get outside of the classroom, you can of course choose any method you want.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On the TI84 is the command called NormalCDF which is found by pressing the button labeled \"2nd\" and then pressing the VARS key. \n" ); document.write( "The command to type in would be NormalCDF(1.13,999) where mu = 0 and sigma = 1 are the default options. \n" ); document.write( "The 999 is to represent some really large number effectively acting as \"infinity\" so to speak.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can also use an online tool such as this \n" ); document.write( "https://davidmlane.com/normal.html \n" ); document.write( "Which is completely free and offers a more intuitive user interface. No need to memorize function commands or what inputs go where. \n" ); document.write( "As a bonus, it offers a really nice diagram as well. \n" ); document.write( "Notice this diagram has the curve entirely above the x axis. \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Whereas WolframAlpha has a flaw to it when offering a diagram. \n" ); document.write( "This is what shows up when you type in P(Z > 1.13) and select the \"referring to statistics\" option. \n" ); document.write( " ![]() \n" ); document.write( "Some parts of this curve are mistakenly below the x axis. That's not good. \n" ); document.write( "I'm not sure why WolframAlpha has this weird flaw. But it's something to keep in mind. \n" ); document.write( "Tutor @MathLover1 appears to have used this slightly faulty diagram. \n" ); document.write( " \n" ); document.write( " |