document.write( "Question 1206829: Hi
\n" );
document.write( "Janet spent 2/7 of her money on 4 dolls and 8 books. She spent the remaining money on 6 dolls 10 toys and 12 books. How many toys could she buy with 6/7 of her money. \n" );
document.write( "
Algebra.Com's Answer #844500 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i get 30 toys.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's my thinking.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you start with:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2/7 * x = 4 dolls and 8 books. \n" ); document.write( "5/7 * x = 6 dolls and 12 books and 10 toys.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6 dolls is 1.5 * 4 dolls. \n" ); document.write( "12 books is 1.5 * 8 books.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 4 dolls and 8 books = 2/7 * x, then 1.5 * (4 dolls and 8 books) = 1.5 * 2/7 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.5 * 2/7 * x = 3/7 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 3/7 * x = 6 dolls and 12 books, then 2/7 * x must be equal to 10 toys.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6/7 * x = 3 * 2/7 * x, therefore you must be able to buy 30 toys with 6/7 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "algebraically it would look like this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let d = number of dolls and b = number of books and let t = number of toys.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 2 equations that need to be solved simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4d + 8b = 2/7 * x \n" ); document.write( "6d + 12b + 10t = 5/7 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by 1.5 and leave the second equation as is to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6d + 12b = 3/7 * x \n" ); document.write( "6d + 12b + 10t = 5/7 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10t = 2/7 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6/7 * x = 3 * 2/7 * x, therefore multiply both sides of that equation by 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30t = 6/7 * x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your answer.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |