document.write( "Question 1206829: Hi
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document.write( "Janet spent 2/7 of her money on 4 dolls and 8 books. She spent the remaining money on 6 dolls 10 toys and 12 books. How many toys could she buy with 6/7 of her money. \n" );
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Algebra.Com's Answer #844499 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Her first purchase of 4 dolls and 8 books cost her 2/7 of her money. \n" ); document.write( "In her second purchase, she bought 6 dolls and 12 books. 6 dolls is 3/2 of 4 dolls, and 12 books is 3/2 of 8 books, so what she spent on dolls and books in the second purchase was 3/2 of what she spent on them in her first purchase. \n" ); document.write( "3/2 of 2/7 is 3/7, so she spent 3/7 of her money on dolls and books in the second purchase. \n" ); document.write( "Together in her two purchases she spent 2/7 + 3/7 = 5/7 of her money on dolls and books. Since she spent all her money, she spent 2/7 of her money on the 10 toys. \n" ); document.write( "6/7 of her money is 3 times as much as 2/7 of her money. If she can buy 10 toys with 2/7 of her money, then she can buy 3*10 = 30 toys with 6/7 of her money. \n" ); document.write( "ANSWER: 30 \n" ); document.write( " \n" ); document.write( " |