document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179588>Question 1179588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> https://ibb.co/vwTrxgh<BR>\n" );
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document.write( "Given: JA = JL; JC bisects Angle AJL<BR>\n" );
document.write( "Prove: KC bisects Angle AKL\r<BR>\n" );
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document.write( "Thank you :)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844496 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In triangle AJK and LJK<BR>\n" );
document.write( "AJ = JL given<BR>\n" );
document.write( "1=2 (given)<BR>\n" );
document.write( "JK common side\r<BR>\n" );
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document.write( "Therefore triangle AJK and LJK are congruent (by SAS test)\r<BR>\n" );
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document.write( "Triangle AKJ is congruent to LKJ  ( congruent angles of congruent triangles)\r<BR>\n" );
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document.write( "Therefore 5=6 \r<BR>\n" );
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document.write( "Therefore KC bisects Angle AKL<BR>\n" );
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