document.write( "Question 559646: a car radiator has a capacity of 16 quartz and is filled with a 25% antifreeze solution. how much must be drained off and replaced with pure antifreeze to obtain a 40% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #844475 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The \"draining off\" and \"replacing\" in the problem only complicates the process of solving the problem. Essentially, you are simply mixing a 25% antifreeze solution with a 100% antifreeze solution to obtain 16 quarts of 40% antifreeze.

\n" ); document.write( "The question asks for the amount of pure antifreeze to be used. So

\n" ); document.write( "x = quarts of 100% antifreeze
\n" ); document.write( "16-x = quarts of 25% antifreeze

\n" ); document.write( "The mixture is 40% antifreeze:

\n" ); document.write( "\"1.00%28x%29%2B.25%2816-x%29=.40%2816%29\"

\n" ); document.write( "I leave it to you to solve the problem by that formal algebraic method. As shown the the other tutors, the answer is 3.2 quarts.

\n" ); document.write( "Here is an informal method that can be used to solve any 2-part mixture problem like this.

\n" ); document.write( "The three percentages in the problem are 25, 40, and 100. Picture (in your mind, or on paper if needed) those three percentages on a number line. Then observe/calculate that 40 is 15/75 = 1/5 of the way from 25 to 100. That means 1/5 of the mixture is the 100% antifreeze.

\n" ); document.write( "1/5 of 16 quarts is 3.2 quarts.

\n" ); document.write( "ANSWER: 3.2 quarts

\n" ); document.write( "
\n" ); document.write( "
\n" );