document.write( "Question 116080: At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.
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Algebra.Com's Answer #84445 by ankor@dixie-net.com(22740)\"\" \"About 
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At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.
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\n" ); document.write( "Since we are dealing in mph,
\n" ); document.write( "Change J's run time to hrs, 30 min = \"1%2F2\" hr
\n" ); document.write( "Change K's run time to hrs, 20 min = \"1%2F3\"hr
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\n" ); document.write( "Let s = Ken's speed (mph) to overtake Joe at 7:30
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\n" ); document.write( "When K overtakes J they will have traveled the same distance
\n" ); document.write( "Write a distance equation: Dist = time * speed
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\n" ); document.write( "K's dist = J's dist
\n" ); document.write( "\"1%2F3\"s = \"1%2F2\"(6)
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\n" ); document.write( "Cross multiply:
\n" ); document.write( "2s = 3(6)
\n" ); document.write( "s = \"18%2F2\"
\n" ); document.write( "s = 9 mph for K to catch up with J at 7:30
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\n" ); document.write( "Check solution by finding that their distances are, indeed, equal:
\n" ); document.write( "\"1%2F2\"(6) = 3 mi
\n" ); document.write( "\"1%2F3\"(9) = 3 mi\r
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