document.write( "Question 116080: At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m.
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Algebra.Com's Answer #84445 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! At 7:00 a.m. Joe starts jogging at 6 mph. At 7:10 a.m. Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 a.m. \n" ); document.write( ": \n" ); document.write( "Since we are dealing in mph, \n" ); document.write( "Change J's run time to hrs, 30 min = \n" ); document.write( "Change K's run time to hrs, 20 min = \n" ); document.write( ": \n" ); document.write( "Let s = Ken's speed (mph) to overtake Joe at 7:30 \n" ); document.write( ": \n" ); document.write( "When K overtakes J they will have traveled the same distance \n" ); document.write( "Write a distance equation: Dist = time * speed \n" ); document.write( ": \n" ); document.write( "K's dist = J's dist \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross multiply: \n" ); document.write( "2s = 3(6) \n" ); document.write( "s = \n" ); document.write( "s = 9 mph for K to catch up with J at 7:30 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding that their distances are, indeed, equal: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |