document.write( "Question 1206798: An important factor in selling a residential property is the number of people who look through the home. A sample of 11 homes recently sold in the Halifax, Nova Scotia, area revealed the mean number looking through each home was 17 and the standard deviation of the sample was 3 people. Develop a 90% confidence interval for the population mean. (Round the final answers to 2 decimal places.)\r
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document.write( "Confidence interval for the population mean is between
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Algebra.Com's Answer #844448 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "mu = population mean = unknown \n" ); document.write( "sigma = population standard deviation = unknown \n" ); document.write( "xbar = 17 = sample mean \n" ); document.write( "s = 3 = sample standard deviation \n" ); document.write( "n = 11 = sample size\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since we do not know the population standard deviation (sigma), and because n > 30 is not the case, we must use the T distribution. \n" ); document.write( "df = degrees of freedom \n" ); document.write( "df = n-1 \n" ); document.write( "df = 11-1 \n" ); document.write( "df = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 90% confidence, and df = 10, the t critical value is roughly t =1.812\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can use a table such as this \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "to determine the t critical value. \n" ); document.write( "Highlight the row that has df = 10. Highlight the column that has \"90%\" at the bottom. \n" ); document.write( "This row and column combo yields the value 1.812 which is approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What this means is that P(-1.812 < t < 1.812) = 0.90 approximately when df = 10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way to determine this t critical value is to use a stats calculator such as a TI84. \n" ); document.write( "The specific function to use on a TI84 is called invT. \n" ); document.write( "There are many other calculators that offer a similar feature.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here are the important values we need \n" ); document.write( "t = 1.812 (approximate) \n" ); document.write( "xbar = 17 \n" ); document.write( "s = 3 \n" ); document.write( "n = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "E = margin of error \n" ); document.write( "E = t*s/sqrt(n) \n" ); document.write( "E = 1.812*3/sqrt(11) \n" ); document.write( "E = 1.639016 approximately\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = lower bound of confidence interval \n" ); document.write( "L = xbar - E \n" ); document.write( "L = 17 - 1.639016 \n" ); document.write( "L = 15.360984 \n" ); document.write( "L = 15.36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = upper bound of confidence interval \n" ); document.write( "U = xbar + E \n" ); document.write( "U = 17 + 1.639016 \n" ); document.write( "U = 18.639016 \n" ); document.write( "U = 18.64\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 90% confidence interval of the format (L, U) is roughly (15.36, 18.64) \n" ); document.write( "This represents 15.36 < mu < 18.64 which is a more descriptive way of explaining what's going on (since it involves the parameter we're trying to estimate).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We are 90% confident that the population mean (mu) is somewhere between 15.36 and 18.64 \n" ); document.write( " \n" ); document.write( " |