document.write( "Question 116112: f(x)=2x^2-3x+5, find f(1)\r
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Algebra.Com's Answer #84444 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=2x%5E2-3x%2B5\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2%281%29%5E2-3%281%29%2B5\" Plug in \"x=1\". In other words, replace each x with 1.\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2%281%29-3%281%29%2B5\" Evaluate \"%281%29%5E2\" to get 1.\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=%2B2-3%281%29%2B5\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=%2B2-3%2B5\" Multiply -3 and 1 to get -3\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=4\" Now combine like terms
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