document.write( "Question 1206795: If the sum of two numbers is 4 and the sum of their squares minus three times their product is 76 find the numbers \n" ); document.write( "
Algebra.Com's Answer #844432 by josgarithmetic(39625)\"\" \"About 
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x and y
\n" ); document.write( "\"system%28x%2By=4%2Cx%5E2%2By%5E2-3xy=76%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4-x\"
\n" ); document.write( "substituting,
\n" ); document.write( "\"x%5E2%2B%284-x%29%5E2-3x%284-x%29=76\"
\n" ); document.write( "\"x%5E2%2B16-8x%2Bx%5E2-12x%2B3x%5E2=76\"
\n" ); document.write( "\"5x%5E2-20x=60\"
\n" ); document.write( "divide both sides by 5,
\n" ); document.write( "\"x%5E2-4x=12\"
\n" ); document.write( "\"x%28x-4%29=12\"
\n" ); document.write( "Could the factors be 6 and 2?\r
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\n" ); document.write( "\n" ); document.write( "\"6%286-4%29=12\" yes.\r
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\n" ); document.write( "\n" ); document.write( "Could the factors of 12 be -6 and -2?
\n" ); document.write( "\"-6%28-6-4%29\"
\n" ); document.write( "\"60\", no.\r
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\n" ); document.write( "\n" ); document.write( "x can be 6.
\n" ); document.write( "If that, then \"y=4-6\"
\n" ); document.write( "\"y=-2\"\r
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\n" ); document.write( "\n" ); document.write( "The numbers, -2 and +6.\r
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\n" ); document.write( "\n" ); document.write( "Check?
\n" ); document.write( "x=6;
\n" ); document.write( "\"6%5E2%2B%28-2%29%5E2-3%2A6%28-2%29\"
\n" ); document.write( "\"36%2B4%2B36\"
\n" ); document.write( "\"72%2B4\"
\n" ); document.write( "\"76\"\r
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\n" ); document.write( "\n" ); document.write( "The numbers are -2 and +6.
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