document.write( "Question 1206756: Suppose that you are performing the probability experiment of rolling one fair six-sided die. Let F be the event of rolling a four or a five. You are interested in how many times you need to roll the die in order to obtain the first four or five as the outcome.
\n" ); document.write( "• p = probability of success (event F occurs)
\n" ); document.write( "• q = probability of failure (event F does not occur)
\n" ); document.write( "Find the values of p and q. (Enter exact numbers as integers, fractions, or decimals.)
\n" ); document.write( "Find the probability that the first occurrence of event F (rolling a four or five) is on the second trial. (Round your answer to four decimal places.)
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Algebra.Com's Answer #844375 by ikleyn(52812)\"\" \"About 
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\n" ); document.write( "Suppose that you are performing the probability experiment of rolling one fair six-sided die.
\n" ); document.write( "Let F be the event of rolling a four or a five. You are interested in how many times you need
\n" ); document.write( "to roll the die in order to obtain the first four or five as the outcome.
\n" ); document.write( "• p = probability of success (event F occurs)
\n" ); document.write( "• q = probability of failure (event F does not occur)
\n" ); document.write( "(a) Find the values of p and q. (Enter exact numbers as integers, fractions, or decimals.)
\n" ); document.write( "(b) Find the probability that the first occurrence of event F (rolling a four or five)
\n" ); document.write( "is on the second trial. (Round your answer to four decimal places.)
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document.write( "(a)  p = probability that \" a four or a five\" occurs (event F).  This probability is\r\n" );
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document.write( "         p = \"1%2F6\" + \"1%2F6\" = \"2%2F6\" = \"1%2F3\".    \r\n" );
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document.write( "     q = probability that event F does not occur.  It is a complementary event to F.\r\n" );
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document.write( "         q = 1 - p = 1 - \"1%2F3\" = \"2%2F3\".\r\n" );
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document.write( "(b)  Probability of (b) is \r\n" );
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document.write( "         P = P(event F is not a first roll; event F is the second roll) = (1-p)*p = q*p = \"%282%2F3%29%2A%281%2F3%29\" = \"2%2F9\".\r\n" );
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