document.write( "Question 29341: A reduction of 10% in the price of tea enables a dealer to purchage 25kg more tea for Rs 22500.What is the reduced price per kg of tea? What was the original price per kg? \n" ); document.write( "
Algebra.Com's Answer #844366 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "For the fixed price of Rs 22500, if the price is reduced by a factor of 9/10 then the amount he can buy for that price increases by a factor of 10/9.

\n" ); document.write( "Let x be the number of kg he could buy at the original price. Then

\n" ); document.write( "\"%28x%2B25%29%2Fx=10%2F9\"
\n" ); document.write( "\"10x=9%28x%2B25%29\"
\n" ); document.write( "\"10x=9x%2B225\"
\n" ); document.write( "\"x=225\"

\n" ); document.write( "At the original price, he could buy x=225 kg of tea; at the reduced price he can buy x+25=250 kg.

\n" ); document.write( "The original price per kg was Rs 22500/225 = Rs 100.

\n" ); document.write( "The reduce price per kg was Rs 22500/250 = Rs 90. (Or, the reduce price per kg was 90% of Rs 100, which is Rs 90.)

\n" ); document.write( "ANSWERS:
\n" ); document.write( "reduced price per kg: Rs 90
\n" ); document.write( "original price per kg: Rs 100

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