document.write( "Question 1206727: A reduction in the price of petrol by 10% enables a motorist to buy 5 gallons more for$180. Find the original price of petrol.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4$ per gallon
\n" ); document.write( "5$ per gallon
\n" ); document.write( "7$ per gallon
\n" ); document.write( "8$ per gallon
\n" ); document.write( "

Algebra.Com's Answer #844338 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"PRICE%2AQUANTITY=COST\"\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "PRICE           QUANTITY gallons        COST dollars\r\n" );
document.write( "\r\n" );
document.write( " p                  180/p                 180\r\n" );
document.write( "\r\n" );
document.write( " 0.9p            180/(0.9p)               180\r\n" );
document.write( "\r\n" );
document.write( "difference            5\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28180%2F%280.9p%29-180%2Fp=5%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"200%2Fp-180%2Fp=5\"\r
\n" ); document.write( "\n" ); document.write( "\"20%2Fp=5\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p=4%29\"
\n" ); document.write( "
\n" );