document.write( "Question 1206695: HighTech Inc. randomly tests its employees about company policies. Last year in the 390 random tests conducted, 12 employees failed the test.\r
\n" ); document.write( "\n" ); document.write( "Develop a 95% confidence interval for the proportion of applicants that fail the test. (Round to three decimal places.)
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Algebra.Com's Answer #844292 by Theo(13342)\"\" \"About 
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test size = 390
\n" ); document.write( "12 out of 390 failed the test
\n" ); document.write( "failure proportion = 12/390\r
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\n" ); document.write( "\n" ); document.write( "p = 12/390
\n" ); document.write( "q = 1 - p = 378/390\r
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\n" ); document.write( "\n" ); document.write( "standard error of a proportion = sqrt(p*q/n) = sqrt(12/390 * 378/390 / 390) = .0087445932.\r
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\n" ); document.write( "\n" ); document.write( "95% two tail confidence interval required a critical z-score of plus or minus 1.959963986.\r
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\n" ); document.write( "\n" ); document.write( "on the low side of the confidence interval, the z-score formula of z = (x - m) / s becomes -1.959963986 = (x - 12/390) / .0087445932.
\n" ); document.write( "solve for x to get x = .013630143.\r
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\n" ); document.write( "\n" ); document.write( "on the high side of the confidence interval, the z-score formula of z = (x - m) / s becomes 1.959963986 = (x - 12/390) / .0087445932.
\n" ); document.write( "solve for x to get x = .0479083186.\r
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\n" ); document.write( "\n" ); document.write( "that should be your 95% confidence interval.
\n" ); document.write( "i used the calculator at https://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "here's what it looks like using that calculator.\r
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\n" ); document.write( "\n" ); document.write( "the calculator truncates inputs to 6 or 7 decimal digits, so i didn't get the full value in there.
\n" ); document.write( "the rounding / truncating is usually good enough to get an accurate answer.\r
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\n" ); document.write( "\n" ); document.write( "from the calculator, you can see that the confidence interval is the area between those two x-scores = .95.\r
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