document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1206671>Question 1206671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express the answer in exact form.\r<BR>\n" );
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document.write( "A regular hexagon with sides of 3\" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.\r<BR>\n" );
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document.write( "(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4 s2 √3.)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #844229 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=844229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you draw this, there are 6 equal equilateral triangles formed by the hexagon with sides 3. The combined area, or the area of the hexagon,  is (6/4)*3^2*sqrt*(3)=13.5 sqrt(3)<BR>\n" );
document.write( "The area of the whole circle is 9pi.<BR>\n" );
document.write( "the area outside the hexagon is 9pi-13.5 sqrt(3)=4.89 in^2<BR>\n" );
document.write( "and the exact area of each segment is 1/6 of that or (1/6)*(9pi-13.5 sqrt(3) </SPAN>\n" );
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