document.write( "Question 1206628: Given the equivalent impedance of a circuit can be calculated by the expression
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Algebra.Com's Answer #844189 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Just in rectangular coordinants:\r\n" );
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document.write( "We math people's \"i\" is you EE people's \"j\".\r\n" );
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document.write( "\"Z=%28Z%5B1%5DZ%5B2%5D%29%2F%28Z%5B1%5D%2BZ%5B2%5D%29\"\r\n" );
document.write( "\"matrix%281%2C2%2Cif%2C+Z%5B1%5D=5j-10%29\"\r\n" );
document.write( "\"matrix%281%2C2%2Cif%2C+Z%5B2%5D=6j-8%29\"\r\n" );
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document.write( "\"Z=%28+%285j-10%29%286j-8%29+%29%2F%28+%285j-10%29%2B%286j-8%29+%29\"\r\n" );
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document.write( "\"Z=+%2830j%5E2-40j-60j%2B80+%29%2F%285j-10%2B6j-8%5E%22%22+%29\"\r\n" );
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document.write( "Since j2 = -1\r\n" );
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document.write( "\"Z=+%2830j%5E2-100j%2B80+%29%2F%2811j-18%5E%22%22+%29\" \r\n" );
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document.write( "\"Z=+%2830%28-1%29-100j%2B80+%29%2F%2811j-18%5E%22%22+%29\" \r\n" );
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document.write( "\"Z=+%28-30-100j%2B80+%29%2F%2811j-18%5E%22%22+%29\"\r\n" );
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document.write( "\"Z=+%28-100j%2B50%29%2F%2811j-18%29\"\r\n" );
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document.write( "\"Z=+%28%28-100j%2B50%29%2F%2811j-18%29%29%28expr%28%2811j%2B18%29%2F%2811j%2B18%29%29%29\"\r\n" );
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document.write( "\"Z=+%28-1100j%5E2-1800j%2B550j%2B900%29%2F%28121j%5E2-324%29\"\r\n" );
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document.write( "\"Z=+%28-1100%28-1%29-1855j%2B900%29%2F%28121%28-1%29-324%29\"\r\n" );
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document.write( "\"Z=+%281100-1250j%2B900%29%2F%28-445%29\"\r\n" );
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document.write( "\"Z=+%28-1250j%2B2000%29%2F%28-445%29\"\r\n" );
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document.write( "Divide top and bottom by -5:\r\n" );
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document.write( "\"Z=+%28250j-400%29%2F89\"\r\n" );
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document.write( "\"Z=expr%28250%2F89%29j-400%2F89\"\r\n" );
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document.write( "\"Z=2.809j-4.494\"\r\n" );
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document.write( "Edwin
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