document.write( "Question 116124: This is homework and I am having issues.\r
\n" ); document.write( "\n" ); document.write( "An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.\r
\n" ); document.write( "\n" ); document.write( "Compute the probability of each of the following events: \r
\n" ); document.write( "\n" ); document.write( "Event A : The sum is greater than 7 .
\n" ); document.write( "Event B: The sum is divisible by 2.
\n" ); document.write( "Write your answers as exact fractions.
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Algebra.Com's Answer #84418 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Since there are six numbers on each die, there are 6 X 6 = 36 total different results when you roll two dice -- which is the same thing as rolling one die twice in succession.\r
\n" ); document.write( "\n" ); document.write( "There is exactly 1 way to get a total of 2: 1 and 1
\n" ); document.write( "There are two ways to get 3: 1 and 2, 2 and 1
\n" ); document.write( "There are three ways to get 4: 1 and 3, 3 and 1, 2 and 2
\n" ); document.write( "four ways to get 5
\n" ); document.write( "five ways to get 6
\n" ); document.write( "six ways to get 7
\n" ); document.write( "five ways to get 8
\n" ); document.write( "four ways to get 9
\n" ); document.write( "three ways to get 10
\n" ); document.write( "two ways to get 11
\n" ); document.write( "one way to get 12\r
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\n" ); document.write( "\n" ); document.write( "For the sum to be greater than 7, it must be 8, 9, 10, 11, or 12 and there are 5 plus 4 plus 3 plus 2 plus 1 ways to get those numbers out of the total of 36.\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2B4%2B3%2B2%2B1%29%2F36=15%2F36\"\r
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\n" ); document.write( "\n" ); document.write( "For the total to be even, you have to get a result of 2, 4, 6, 8, 10, or 12, and there are 1 plus 3 plus 5 plus 5 plus 3 plus 1 ways to get these results out of the total of 36 possible.\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2B3%2B5%2B5%2B3%2B1%29%2F36=18%2F36=1%2F2\".
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