document.write( "Question 1206609: You deposit $6000 into an account that earns 7% compounded annually. A friend deposits $5500 into an account that earns 6.95% annual interest, compounded continuously. Will your friend's balance ever equal yours? If so, when? If not, enter NEVER.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #844171 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "You deposit $6000 into an account that earns 7% compounded annually.
\n" ); document.write( "A friend deposits $5500 into an account that earns 6.95% annual interest, compounded continuously.
\n" ); document.write( "Will your friend's balance ever equal yours? If so, when? If not, enter NEVER.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "For your account, the effective annual growth coefficient is 1.07.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "For your friend's account, the effective annual growth coefficient is \r\n" );
document.write( "\r\n" );
document.write( "    \"e%5E0.0695\" = \"2.71828%5E0.0695\" = 1.071972011.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "As you see, for your friend's account, the effective annual coefficient is greater than your, \r\n" );
document.write( "so the friend's account is growing faster and will catch with your account somewhen.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "To find this catching time moment , write an equation\r\n" );
document.write( "\r\n" );
document.write( "    \"6000%2A%281%2B0.07%29%5Et\" = \"5500%2Ae%5E%280.0695t%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It gives\r\n" );
document.write( "\r\n" );
document.write( "    \"6000%2F5500\" = \"e%5E%280.0695t%29%2F1.07%5Et\",\r\n" );
document.write( "\r\n" );
document.write( "    1.090909091 = \"%282.71828%5E0.0695%2F1.07%29%5Et\", \r\n" );
document.write( "\r\n" );
document.write( "    1.090909091 = \"1.001843001%5Et\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Take logarithm base 10 of both sides\r\n" );
document.write( "\r\n" );
document.write( "    log(1.090909091) = log(1.001843001)*t\r\n" );
document.write( "\r\n" );
document.write( "and find t\r\n" );
document.write( "\r\n" );
document.write( "    t = \"log%28%281.090909091%29%29%2Flog%28%281.001843001%29%29\" = 47.25528282 years.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Now round 47.25528282 to the closest greater integer year and get the\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER. Your friend's account will be greater than yours in 48 years.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "I rounded 47.25528282 to 48 years in order for the bank be able to make the last compounding \r\n" );
document.write( "with your account to compare the accounts in the same time moment in equal conditions.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );