document.write( "Question 1206577: Assume that the readings on the thermometers are normally distributed with a mean of 0 degree and a standard deviation of 1.00 degree. Find the indicated probability, where z is the reading in degrees.\r
\n" ); document.write( "\n" ); document.write( "a) Between 0 and 1.96\r
\n" ); document.write( "\n" ); document.write( "b) Less than -1.47\r
\n" ); document.write( "\n" ); document.write( "c) Between 0.89 and 1.78\r
\n" ); document.write( "\n" ); document.write( "d) Greater than -1.05 \n" ); document.write( "

Algebra.Com's Answer #844136 by ikleyn(52921) $\"\"$ $\"About$

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\n" ); document.write( "Assume that the readings on the thermometers are normally distributed
\n" ); document.write( "with a mean of 0 degree and a standard deviation of 1.00 degree.
\n" ); document.write( "Find the indicated probability, where z is the reading in degrees.
\n" ); document.write( "a) Between 0 and 1.96
\n" ); document.write( "b) Less than -1.47
\n" ); document.write( "c) Between 0.89 and 1.78
\n" ); document.write( "d) Greater than -1.05
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\n" ); document.write( "\n" ); document.write( "

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document.write( "(a)  This probability is the area under the given/described normal curve \r\n" );
document.write( "     between the z-marks z1 = 0 and z2 = 1.96.\r\n" );
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document.write( "     Use a regular calculator TI-83/84 and its standard function normcdf.\r\n" );
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document.write( "                      z1    z2   mean   SD      <<<---=== formatting pattern\r\n" );
document.write( "         P = normcdf( 0,   1.96,  0,   1.00).\r\n" );
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document.write( "     You will get the value  P = 0.475   (rounded).    ANSWER\r\n" );
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document.write( "     The same can be done using an online (free of charge) calculator\r\n" );
document.write( "     https://onlinestatbook.com/2/calculators/normal_dist.html\r\n" );
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document.write( "(b)  This probability is the area under the given/described normal curve \r\n" );
document.write( "     on the left of the z-mark z2 = -1.47.\r\n" );
document.write( "\r\n" );
document.write( "     Use a regular calculator TI-83/84 and its standard function normcdf.\r\n" );
document.write( "\r\n" );
document.write( "                      z1        z2   mean   SD      <<<---=== formatting pattern\r\n" );
document.write( "         P = normcdf( -9999,  -1.47,  0,   1.00).\r\n" );
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document.write( "\r\n" );
document.write( "     You will get the value  P = 0.0708   (rounded).    ANSWER\r\n" );
document.write( "\r\n" );
document.write( "     The same can be done using an online (free of charge) calculator\r\n" );
document.write( "     https://onlinestatbook.com/2/calculators/normal_dist.html\r\n" );
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document.write( "(c)  This case is similar (a TWIN) to case (a).  Do it as instructed in (a),\r\n" );
document.write( "     with obvious modifications.\r\n" );
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document.write( "(d)  This probability is the area under the given/described normal curve \r\n" );
document.write( "     on the right of the z-mark z1 = -1.05.\r\n" );
document.write( "\r\n" );
document.write( "     Use a regular calculator TI-83/84 and its standard function normcdf.\r\n" );
document.write( "\r\n" );
document.write( "                        z1     z2   mean   SD      <<<---=== formatting pattern\r\n" );
document.write( "         P = normcdf( -1.05,  9999,  0,   1.00).\r\n" );
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document.write( "\r\n" );
document.write( "     You will get the value  P = 0.8531   (rounded).    ANSWER\r\n" );
document.write( "\r\n" );
document.write( "     The same can be done using an online (free of charge) calculator\r\n" );
document.write( "     https://onlinestatbook.com/2/calculators/normal_dist.html\r\n" );
document.write( "

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\n" ); document.write( "\n" ); document.write( "Solved.\r
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