document.write( "Question 1206571: Use the probability distribution for the random variable x to answer the question.
\n" ); document.write( "x 0 1 2 3 4 5
\n" ); document.write( "p(x)
\n" ); document.write( "0.35 0.2 0.19 0.17 0.06 0.03
\n" ); document.write( "Locate the interval
\n" ); document.write( "𝜇 ± 2𝜎
\n" ); document.write( " on the x-axis of a probability histogram. You are given that the mean is 1.48 and the standard deviation is 1.42. What is the probability that x will fall into this interval?
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Algebra.Com's Answer #844132 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "𝜇 = greek letter mu = mean = 1.48
\n" ); document.write( "𝜎 = greek letter sigma = standard deviation = 1.42\r
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\n" ); document.write( "\n" ); document.write( "𝜇 ± 2𝜎 breaks down into 𝜇 - 2𝜎 and 𝜇 + 2𝜎\r
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\n" ); document.write( "\n" ); document.write( "This will mean 𝜇 - 2𝜎 < x < 𝜇 + 2𝜎\r
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\n" ); document.write( "\n" ); document.write( "𝜇 - 2𝜎 = 1.48 - 2*1.42 = -1.36
\n" ); document.write( "𝜇 + 2𝜎 = 1.48 + 2*1.42 = 4.32\r
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\n" ); document.write( "\n" ); document.write( "We're focused on the interval -1.36 < x < 4.32\r
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\n" ); document.write( "\n" ); document.write( "If x is an integer then we focus on the sub-interval \"-1+%3C=+x+%3C=+4\"
\n" ); document.write( "Furthermore, the smallest x can be in this case is x = 0, so we're really only going to focus on \"0+%3C=+x+%3C=+4\"\r
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\n" ); document.write( "\n" ); document.write( "Add up the probability values associated with x = 0 through x = 4.
\n" ); document.write( "P(0)+P(1)+P(2)+P(4) = 0.35+0.2+0.19+0.17+0.06 = 0.97 which is the final answer\r
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\n" ); document.write( "\n" ); document.write( "Or as an alternate route
\n" ); document.write( "P(5) = 0.03
\n" ); document.write( "P(value between 0 and 4) = 1 - P(5) = 1 - 0.03 = 0.97\r
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\n" ); document.write( "\n" ); document.write( "There's a 97% chance of picking an x value between 0 and 4 inclusive of both endpoints.
\n" ); document.write( "This is equivalent to saying there's a 97% chance of picking an x value such that -1.36 < x < 4.32; where each endpoint is two standard deviations away from the mean.\r
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\n" ); document.write( "\n" ); document.write( "Answer: 0.97
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