document.write( "Question 1206559: Suppose that 20,000 married adults in a country were randomly surveyed as to the number of children they have. The results are compiled and are used as theoretical probabilities. Let X = the number of children married people have.
\n" ); document.write( "x P(x) xP(x)
\n" ); document.write( "0 0.15
\n" ); document.write( "1 0.20
\n" ); document.write( "2 0.35
\n" ); document.write( "3
\n" ); document.write( "4 0.10
\n" ); document.write( "5 0.05
\n" ); document.write( "6 (or more) 0.05
\n" ); document.write( "(a) Find the probability that a married adult has three children. (Enter your answer to two decimal places.)
\n" ); document.write( "(c) Find the expected value. (Enter your answer to two decimal place.)
\n" ); document.write( "

Algebra.Com's Answer #844114 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "X = number of children married people have
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
xP(x)
00.15
10.20
20.35
3????
40.10
50.05
6 (or more)0.05

\n" ); document.write( "The two key rules for a probability distribution are:
  • Each P(x) item must be between 0 and 1.
  • All of the P(x) values must add to 1.
So,
\n" ); document.write( "P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6) = 1
\n" ); document.write( "0.15+0.20+0.35+P(3)+0.10+0.05+0.05 = 1
\n" ); document.write( "0.9+P(3) = 1
\n" ); document.write( "P(3) = 1 - 0.9
\n" ); document.write( "P(3) = 0.1\r
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\n" ); document.write( "\n" ); document.write( "The probability a married adult has exactly 3 kids is 0.1\r
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\n" ); document.write( "\n" ); document.write( "This is what the completed table will look like
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
xP(x)
00.15
10.20
20.35
30.10
40.10
50.05
6 (or more)0.05
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now to fill out the column labeled x*P(x).
\n" ); document.write( "As the name of this column suggests, we'll multiply each paired x and P(x) value.
\n" ); document.write( "Eg: 0*0.15 = 0 and 1*0.20 = 0.20
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "
xP(x)x*P(x)
00.150
10.200.20
20.350.70
30.100.30
40.100.40
50.050.25
6 (or more)0.050.30

\n" ); document.write( "The \"6 (or more)\" entry at the bottom is treated simply as x = 6. I wasn't sure how to handle that portion.
\n" ); document.write( "Spreadsheet software is recommended. But since the table is fairly small, doing it by hand isn't that bad. \r
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\n" ); document.write( "\n" ); document.write( "Add up the values in the x*P(x) column to arrive at the expected value 2.15
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