document.write( "Question 1206563: Suppose a designer has a palette of 11 colors to work with, and wants to design a flag with 4 vertical stripes, all of different colors.\r
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document.write( "How many possible flags can be created? \n" );
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Algebra.Com's Answer #844110 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if he cares how the stripes are arranged, then the formula is p(11,4).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if he only cares about the colors and is not concerned with their position in the flag, then the formula is c(11,4).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since many flags have the same colors in different arrangement, then i would thin that p(11,4) would be more applicable.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c(11,4) = 11! / (4! * 7!) = (11 * 10 * 9 * 8) / (4 * 3 * 2 * 1) = 330\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(11,4) = 11! / (7!) = (11 * 10 * 9 * 8) = 7920\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the difference between c(n,x) and p(n,x) is as follows.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "suppose n = 3 and x = 2 and the 3 elements to choose from are ABC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c(3,2) = 3! / 2! = (3 * 2 * 1) / (2 * 1) = 3. \n" ); document.write( "p(3,2) = 3! / 1! = (3 * 2) = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the number of combinations is 3. \n" ); document.write( "they are: AB, AC, BC \n" ); document.write( "the number of permutations is 6. \n" ); document.write( "they are: AB, BA, AC, CA, BC, CB.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with combinations, AB and BA are considered part of the same set because the order of the elements within the set is not important.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with permutations, AB and BA are considered different sets because the order of the elements within the set is important.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if two countries had the same colors and the same shape, then the only thing that would distinguish them would be the order of the colors in the flag.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i would go with the permutations number of 7920.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the possible ordering of the 4 different colors would be 4! = 4 * 3 * 2 * 1 = 24.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you take that away, then you get the number of combinations because 7920 / 24 = 330. \n" ); document.write( " \n" ); document.write( " |