document.write( "Question 1206560: People visiting video rental stores often rent more than one DVD at a time. The probability distribution for DVD rentals per customer at Video To Go is given in the table below. There is a five-video limit per customer at this store, so nobody ever rents more than five DVDs.
\n" ); document.write( "x P(x)
\n" ); document.write( "0 0.05
\n" ); document.write( "1 0.52
\n" ); document.write( "2 0.23
\n" ); document.write( "3
\n" ); document.write( "4 0.07
\n" ); document.write( "5 0.04
\n" ); document.write( "(a) Find the probability that a customer rents three DVDs. (Enter an exact number as an integer, fraction, or decimal.)
\n" ); document.write( "(b) Find the probability that a customer rents at least four DVDs. (Enter an exact number as an integer, fraction, or decimal.)
\n" ); document.write( "(c) Find the probability that a customer rents at most two DVDs. (Enter an exact number as an integer, fraction, or decimal.)
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #844109 by ikleyn(52835) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "(a)  P(3) is the complement of the sum P(0) + P(1) + P(2) + P(4) + P(5).\r\n" );
document.write( "\r\n" );
document.write( "     So, calculate P =  P(0) + P(1) + P(2) + P(4) + P(5) using given data.\r\n" );
document.write( "\r\n" );
document.write( "     then find P(3) = 1 - P.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(b)  P(at least 4 DVDs) = P(4) + P(5).  Calculate using given data.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "(c)  P(at most 2 DVDs) = P(0) + P(1) + P(2).  Calculate using given data.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Happy calculations !\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );