document.write( "Question 1199027: 1) A man had two employments on the same day with the following salary condition:The first employment is #300000 per annum with annual imcrement of #12000. The second employment with annual salary of #280000 and the annual increment of #15000. The man decided that he will accept the employment that will give him more earnings in the first 15years of service. Which employment should he accept?\r
\n" ); document.write( "\n" ); document.write( "2)A man earns a salary of #2500 per annum. If a rise of #500 is given at the end of each year, find
\n" ); document.write( "a) the total amount the man will earn in 18years
\n" ); document.write( "b) the amount the man will earn in the 20th year
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Algebra.Com's Answer #844087 by mananth(16946)\"\" \"About 
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1) A man had two employments on the same day with the following salary condition:The first employment is #300000 per annum with annual imcrement of #12000. The second employment with annual salary of #280000 and the annual increment of #15000. The man decided that he will accept the employment that will give him more earnings in the first 15years of service. Which employment should he accept?\r
\n" ); document.write( "\n" ); document.write( "First employment
\n" ); document.write( "$300000 per annum with annual imcrement of $12000.
\n" ); document.write( "Time period considered = 15 years
\n" ); document.write( "The yearly increment is constant =12000
\n" ); document.write( "Using
\n" ); document.write( "Arithmetic sequence formula for earnings at end of 15 years\r
\n" ); document.write( "\n" ); document.write( "\"+Sn+=+%28n%2F2%29%282a%2B%28n-1%29d%29+\"\r
\n" ); document.write( "\n" ); document.write( "a=300000 d=12000, n=15\r
\n" ); document.write( "\n" ); document.write( "\"+S15+=+%2815%2F2%29%282%2A300000%2B%2815-1%29%2A12000%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+S15+=+%2815%2F2%29%28600000%2B%2814%29%2A12000%29+\"
\n" ); document.write( "S15 = 5,760,000\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Second employment\r
\n" ); document.write( "\n" ); document.write( "280000 and the annual increment of #15000
\n" ); document.write( "a= 280000 d=15000, n=15\r
\n" ); document.write( "\n" ); document.write( "S15 = (15/2)*(2*280000+(15-1)*15000\r
\n" ); document.write( "\n" ); document.write( "S(15)= 5,775,000\r
\n" ); document.write( "\n" ); document.write( "Now he can decide\r
\n" ); document.write( "\n" ); document.write( " The second employment offers higher earnings in the first 15 years\r
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