document.write( "Question 1064005: ΔABC has vertices at A(5,2), B(−3,1), and C(−2,5). Point D is located on the intersection of the altitude and AB�, in such a way that D has coordinates at approximately (−1.52,1.18).\r
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document.write( "Match each question with the correct measurement, rounded to one decimal place.\r
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document.write( "What is the approximate area of the triangle?
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document.write( "What is the approximate length of the base of the triangle for the given altitude?
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document.write( "What is the approximate length of the altitude of the triangle?
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document.write( "16.1 units
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document.write( "3.9 units
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document.write( "8.1 units
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document.write( "7.6 units
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document.write( "15.8 units
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document.write( "8.0 units
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Algebra.Com's Answer #844063 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "Area = 15.8 square units \n" ); document.write( "Base = 8.1 units \n" ); document.write( "Altitude = 3.9 units\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Explanation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the distance formula to determine the length of side AB \n" ); document.write( "A = (x1,y1) = (5,2) and B = (x2,y2) = (-3,1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Follow similar steps to find the distance from C = (-2,5) to D = (-1.52,1.18) is roughly 3.85004 which rounds to 3.9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "area of triangle = 0.5*base*height \n" ); document.write( "area = 0.5*AB*CD \n" ); document.write( "area = 0.5*8.1*3.9 \n" ); document.write( "area = 15.795 \n" ); document.write( "area = 15.8 square units.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There's rounding error going on here. \n" ); document.write( "The area of triangle ABC should be 15.5 square units exactly. \n" ); document.write( "This can be determined in the next section below.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When given the coordinates of the vertex points, we could use the shoelace formula to fairly quickly find the area of any polygon. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given list of vertex points \n" ); document.write( "(5,2) \n" ); document.write( "(-3,1) \n" ); document.write( "(-2,5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Make a copy of the first point (5,2) and place it at the bottom of the list \n" ); document.write( "(5,2) \n" ); document.write( "(-3,1) \n" ); document.write( "(-2,5) \n" ); document.write( "(5,2) \n" ); document.write( "This will help form a loop.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Space the x and y coordinates out. Each (x,y) point gets its own row. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then draw in the diagonals as indicated below. \n" ); document.write( " \n" ); document.write( "Multiply along the red diagonal pairs and add up those products. \n" ); document.write( "5*1+(-3*5)+(-2*2) = 5-15-4 = -14 \n" ); document.write( "Do the same for the blue diagonal pairs. \n" ); document.write( "5*5+(-2*1)+(-3*2) = 25-2-6 = 17\r \n" ); document.write( "\n" ); document.write( "Subtract the results. \n" ); document.write( "red - blue = -14 - 17 = -31\r \n" ); document.write( "\n" ); document.write( "We get a negative result. Let's take the absolute value to get |-31| = 31\r \n" ); document.write( "\n" ); document.write( "Lastly, take half of this to get the area = (1/2)*31 = 15.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area of the triangle is exactly 15.5 square units. \n" ); document.write( "GeoGebra can be used to verify.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "More practice on the shoelace formula is found here\r \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What's another way to see how the area is exactly 15.5?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "My post is already quite lengthy so this section will be a brief overview rather than getting into the gritty details. \n" ); document.write( "The distance formula will show that \n" ); document.write( "AB = sqrt(65)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation of line AB is y = (1/8)x + 11/8 \n" ); document.write( "The equation of line CD is y = -8x - 11 \n" ); document.write( "Intersect those two equations to determine point D is at the exact location (-99/65, 77/65) \n" ); document.write( "Note how -99/65 = -1.52 and 77/65 = 1.18 approximately. \n" ); document.write( "So that's where your teacher is getting (-1.52, 1.18) for point D.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the distance formula to determine that CD = 31/sqrt(65)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then lastly, \n" ); document.write( "area = 0.5*base*height \n" ); document.write( "area = 0.5*AB*CD \n" ); document.write( "area = 0.5*sqrt(65)*( 31/sqrt(65) ) \n" ); document.write( "area = 0.5*31 \n" ); document.write( "area = 15.5 \n" ); document.write( "which is exact without any rounding done to it. \n" ); document.write( " \n" ); document.write( " |