document.write( "Question 1064005: ΔABC has vertices at A(5,2), B(−3,1), and C(−2,5). Point D is located on the intersection of the altitude and AB�, in such a way that D has coordinates at approximately (−1.52,1.18).\r
\n" ); document.write( "\n" ); document.write( "https://cds.flipswitch.com/tools/asset/media/607812\r
\n" ); document.write( "\n" ); document.write( "Match each question with the correct measurement, rounded to one decimal place.\r
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\n" ); document.write( "What is the approximate area of the triangle?
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\n" ); document.write( "What is the approximate length of the base of the triangle for the given altitude?
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\n" ); document.write( "What is the approximate length of the altitude of the triangle?
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\n" ); document.write( "16.1 units
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\n" ); document.write( "3.9 units
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\n" ); document.write( "8.1 units
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\n" ); document.write( "7.6 units
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\n" ); document.write( "15.8 units
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\n" ); document.write( "8.0 units
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Algebra.Com's Answer #844063 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Answers:
\n" ); document.write( "Area = 15.8 square units
\n" ); document.write( "Base = 8.1 units
\n" ); document.write( "Altitude = 3.9 units\r
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\n" ); document.write( "\n" ); document.write( "Explanation\r
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\n" ); document.write( "\n" ); document.write( "Use the distance formula to determine the length of side AB
\n" ); document.write( "A = (x1,y1) = (5,2) and B = (x2,y2) = (-3,1)
\n" ); document.write( "\"d+=+sqrt%28+%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28+%285-%28-3%29%29%5E2+%2B+%282-1%29%5E2+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28+%285%2B3%29%5E2+%2B+%282-1%29%5E2+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28+%288%29%5E2+%2B+%281%29%5E2+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28+64+%2B+1+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+sqrt%28+65+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d+=+8.0623\" approximately \r
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\n" ); document.write( "\n" ); document.write( "\"d+=+8.1\"\r
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\n" ); document.write( "\n" ); document.write( "Follow similar steps to find the distance from C = (-2,5) to D = (-1.52,1.18) is roughly 3.85004 which rounds to 3.9\r
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\n" ); document.write( "\n" ); document.write( "Then,
\n" ); document.write( "area of triangle = 0.5*base*height
\n" ); document.write( "area = 0.5*AB*CD
\n" ); document.write( "area = 0.5*8.1*3.9
\n" ); document.write( "area = 15.795
\n" ); document.write( "area = 15.8 square units.\r
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\n" ); document.write( "\n" ); document.write( "There's rounding error going on here.
\n" ); document.write( "The area of triangle ABC should be 15.5 square units exactly.
\n" ); document.write( "This can be determined in the next section below.\r
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\n" ); document.write( "\n" ); document.write( "When given the coordinates of the vertex points, we could use the shoelace formula to fairly quickly find the area of any polygon. \r
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\n" ); document.write( "\n" ); document.write( "Given list of vertex points
\n" ); document.write( "(5,2)
\n" ); document.write( "(-3,1)
\n" ); document.write( "(-2,5)\r
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\n" ); document.write( "\n" ); document.write( "Make a copy of the first point (5,2) and place it at the bottom of the list
\n" ); document.write( "(5,2)
\n" ); document.write( "(-3,1)
\n" ); document.write( "(-2,5)
\n" ); document.write( "(5,2)
\n" ); document.write( "This will help form a loop.\r
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\n" ); document.write( "\n" ); document.write( "Space the x and y coordinates out. Each (x,y) point gets its own row.
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\n" ); document.write( "\n" ); document.write( "Then draw in the diagonals as indicated below.
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\n" ); document.write( "Multiply along the red diagonal pairs and add up those products.
\n" ); document.write( "5*1+(-3*5)+(-2*2) = 5-15-4 = -14
\n" ); document.write( "Do the same for the blue diagonal pairs.
\n" ); document.write( "5*5+(-2*1)+(-3*2) = 25-2-6 = 17\r
\n" ); document.write( "\n" ); document.write( "Subtract the results.
\n" ); document.write( "red - blue = -14 - 17 = -31\r
\n" ); document.write( "\n" ); document.write( "We get a negative result. Let's take the absolute value to get |-31| = 31\r
\n" ); document.write( "\n" ); document.write( "Lastly, take half of this to get the area = (1/2)*31 = 15.5\r
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\n" ); document.write( "\n" ); document.write( "The area of the triangle is exactly 15.5 square units.
\n" ); document.write( "GeoGebra can be used to verify.\r
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\n" ); document.write( "\n" ); document.write( "More practice on the shoelace formula is found here\r
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\n" ); document.write( "\n" ); document.write( "What's another way to see how the area is exactly 15.5?\r
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\n" ); document.write( "\n" ); document.write( "My post is already quite lengthy so this section will be a brief overview rather than getting into the gritty details.
\n" ); document.write( "The distance formula will show that
\n" ); document.write( "AB = sqrt(65)\r
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\n" ); document.write( "\n" ); document.write( "The equation of line AB is y = (1/8)x + 11/8
\n" ); document.write( "The equation of line CD is y = -8x - 11
\n" ); document.write( "Intersect those two equations to determine point D is at the exact location (-99/65, 77/65)
\n" ); document.write( "Note how -99/65 = -1.52 and 77/65 = 1.18 approximately.
\n" ); document.write( "So that's where your teacher is getting (-1.52, 1.18) for point D.\r
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\n" ); document.write( "\n" ); document.write( "Use the distance formula to determine that CD = 31/sqrt(65)\r
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\n" ); document.write( "\n" ); document.write( "Then lastly,
\n" ); document.write( "area = 0.5*base*height
\n" ); document.write( "area = 0.5*AB*CD
\n" ); document.write( "area = 0.5*sqrt(65)*( 31/sqrt(65) )
\n" ); document.write( "area = 0.5*31
\n" ); document.write( "area = 15.5
\n" ); document.write( "which is exact without any rounding done to it.
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