document.write( "Question 1206509: If 2ˣ = 4^y = 8^z and 1/2x + 1/4y + 1/8z = 22/7, show that:
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Algebra.Com's Answer #844040 by ikleyn(52866) $\"\"$ $\"About$

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\n" ); document.write( "If 2ˣ = 4^y = 8^z and 1/2x + 1/4y + 1/8z = 22/7, show that
\n" ); document.write( "x = 7/16, y = 7/32 and z = 7/48
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document.write( "From the given part   =  = ,  we have\r\n" );
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document.write( "     =  = .\r\n" );
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document.write( "It gives us  x = 2y = 3z,  or  y = ,  z = .\r\n" );
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document.write( "Now substitute it into equation\r\n" );
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document.write( "     +  +  = .\r\n" );
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document.write( "You will get\r\n" );
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document.write( "     +  +  = ,\r\n" );
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document.write( "or\r\n" );
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document.write( "     +  +  = ,\r\n" );
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document.write( "     +  +  = ,\r\n" );
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document.write( "     = ,\r\n" );
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document.write( "     = ,\r\n" );
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document.write( "    x =  = .\r\n" );
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document.write( "Then   y =  = ,  z =  = ,   QED.\r\n" );
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