document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116010>Question 116010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is not exactly what my problem is but it's the closest thing I could understand. The problem says \"Coffee worth $3.75 a pound was mixed with coffee worth $4.35 a pound to produce a blend worth $4.11 a pound. How much of each kind of  coffee was used to produce 40 pounds of blended coffee?\" My problem is finding the equations to solve by elimination because, this seems to need 3 variables in order to be made into the first equation. Hope I explained it well enough for you to help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84404 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one variable is plenty\r<BR>\n" );
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document.write( "let x=\"$3.75 coffee\", so 40-x=\"$4.35 coffee\" ___ working in cents to avoid decimals\r<BR>\n" );
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document.write( "375(x)+435(40-x)=411(40) ___ 375x+17400-435x=16440 ___ -60x=-960 </SPAN>\n" );
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