document.write( "Question 116009: CAN SOMEONE HELP ME SOLVE THIS GRAPHING?
\n" ); document.write( " 1. DESCRIBE THE TRANSFORMATIONSON ON A GRAPH OF f(x)=e^x. State the placement of the horizonal asympotote and y-intercept after the transformation. For example,\"left 1\" or \"rotated about the y-axis\" are descriptions
\n" ); document.write( " a) g(x)=e^x+3
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\n" ); document.write( " b)H(x)=e^-x
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\n" ); document.write( " Horizonal asymptote:
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Algebra.Com's Answer #84400 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Description of transformation:\r
\n" ); document.write( "\n" ); document.write( "Remember, \"f%28x%29\" is the same as \"y\". So this means \"y=e%5Ex\".\r
\n" ); document.write( "\n" ); document.write( "So when we say \"e%5Ex%2B3\", we're also saying \"y%2B3\" (replace \"e%5Ex\" with y). So this means we're adding 3 to each y value which graphically shows us that we're shifting each y value up 3 units. \r
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\n" ); document.write( "\n" ); document.write( "So the transformation \"g%28x%29=e%5Ex%2B3\" simply shifts the entire curve up 3 units.\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"f%28x%29\" and \"g%28x%29\", we get\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+exp%28x%29%2Cexp%28x%29%2B3%29+\" Graph of \"f%28x%29=e%5Ex\" (red) and \"h%28x%29=e%5Ex%2B3\" (green)\r
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\n" ); document.write( "\n" ); document.write( "and we can visually verify the transformation\r
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\n" ); document.write( "\n" ); document.write( "Horizontal Asymptote:\r
\n" ); document.write( "\n" ); document.write( "Now if we found the asymptote of \"y=e%5Ex\", we would find that the asymptote is \"y=0\". Since we're translating each point on \"y=e%5Ex\" up 3 units, we're also translating the horizontal asymptote up 3 units. \r
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\n" ); document.write( "\n" ); document.write( "So the new horizontal asymptote is \"y=3\".\r
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\n" ); document.write( "\n" ); document.write( "Also, you can visually verify this answer by looking at the graph above\r
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\n" ); document.write( "\n" ); document.write( "y-intercept in (x, y) form:\r
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\n" ); document.write( "\n" ); document.write( "If we let x=0 and plug it into \"y=e%5Ex\", we get\r
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\n" ); document.write( "\n" ); document.write( "\"y=e%5E0\" Plug in x=0\r
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\n" ); document.write( "\n" ); document.write( "\"y=1\" Raise e to the zeroth power to get one. Remember any number x to the zeroth power is always one (ie \"x%5E0=1\")\r
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\n" ); document.write( "\n" ); document.write( "So for \"f%28x%29\" the y-intercept is (0,1)\r
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\n" ); document.write( "\n" ); document.write( "Now if \"g%28x%29\" translates each y value up 3 units, then simply add 3 to the y-coordinate of the y-intercept to get\r
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\n" ); document.write( "\n" ); document.write( "(0,1+3)---->(0,4)\r
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\n" ); document.write( "\n" ); document.write( "So the new y-intercept is (0,4)\r
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\n" ); document.write( "\n" ); document.write( "Once again, you can visually verify this answer by looking at the graph above\r
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\n" ); document.write( "\n" ); document.write( "Description of transformation:\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"h%28x%29=e%5E%28-x%29\", notice how the exponent is negated. So let's see what affect this transformation has on \"f%28x%29=e%5Ex\", \r
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\n" ); document.write( "\n" ); document.write( " \"h%28x%29=e%5E%28-x%29\" Start with the given transformation \r
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\n" ); document.write( "\n" ); document.write( " \"h%28-2%29=e%5E%28-%28-2%29%29\" Plug in x=-2\r
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\n" ); document.write( "\n" ); document.write( " \"h%28-2%29=e%5E%282%29\" Negate \"-%28-2%29\" to get 2\r
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\n" ); document.write( "\n" ); document.write( "Notice if we plug in x=2 into \"f%28x%29=e%5Ex\", we get \"f%282%29=e%5E2\"\r
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\n" ); document.write( "\n" ); document.write( " \"h%28x%29=e%5E%28-x%29\" Start with the given transformation \r
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\n" ); document.write( "\n" ); document.write( " \"h%28-1%29=e%5E%28-%28-1%29%29\" Plug in x=-1\r
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\n" ); document.write( "\n" ); document.write( " \"h%28-1%29=e%5E%281%29\" Negate \"-%28-1%29\" to get 1\r
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\n" ); document.write( "\n" ); document.write( " \"h%28-1%29=e\" Remove the exponent of 1\r
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\n" ); document.write( "\n" ); document.write( "Notice if we plug in x=1 into \"f%28x%29=e%5Ex\", we get \"f%281%29=e%5E1=e\"\r
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\n" ); document.write( "\n" ); document.write( "So if we take the opposite of x (to get -x), and plug that into g(x), we'll get the same f(x) answer.\r
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\n" ); document.write( "\n" ); document.write( "So what this does is simply reflect the entire graph over the y-axis\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"f%28x%29\" and \"g%28x%29\", we get\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+exp%28x%29%2Cexp%28-x%29%29+\" Graph of \"f%28x%29=e%5Ex\" (red) and \"h%28x%29=e%5E%28-x%29\" (green)\r
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\n" ); document.write( "\n" ); document.write( "and we can visually verify the transformation\r
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\n" ); document.write( "\n" ); document.write( "Horizontal Asymptote:\r
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\n" ); document.write( "\n" ); document.write( "Since we reflected the graph with respect to the y-axis, the horizontal asymptote of \"h%28x%29=e%5E%28-x%29\" is the same as \"f%28x%29=e%5Ex\" (you can see this from the graph above) \r
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\n" ); document.write( "\n" ); document.write( "So the horizontal asymptote is \"y=0\"\r
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\n" ); document.write( "\n" ); document.write( "Note: you can visually verify this answer by looking at the graph above\r
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\n" ); document.write( "\n" ); document.write( "y-intercept in (x, y) form:\r
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\n" ); document.write( "\n" ); document.write( "Since the line of symmetry between the two graphs is the line x=0 (ie the y axis), this means that the point that intersects with the y-axis is reflected to itself. So essentially the y-intercept does not change also. Once again, you can visually verify this using the graph above.\r
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\n" ); document.write( "\n" ); document.write( "So the y-intercept is (0,1)\r
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\n" ); document.write( "\n" ); document.write( "Once again, you can visually verify this answer by looking at the graph above
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