document.write( "Question 1206477: A rectangle has a 24-foot perimeter. The width is exactly 1/2 of its length. What is the area in square feet? \n" ); document.write( "
Algebra.Com's Answer #843987 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "A rectangle has a \"24\"-foot perimeter. \r
\n" ); document.write( "\n" ); document.write( "\"2%28L%2BW%29=24\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=12\"\r
\n" ); document.write( "\n" ); document.write( "if the width is exactly \"1%2F2\" of its length, we have\r
\n" ); document.write( "\n" ); document.write( "\"W=L%2F2\"\r
\n" ); document.write( "\n" ); document.write( "substitute in\r
\n" ); document.write( "\n" ); document.write( "\"L%2BL%2F2=12\"\r
\n" ); document.write( "\n" ); document.write( "\"3L%2F2=12\"\r
\n" ); document.write( "\n" ); document.write( "\"L=24%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"L=8ft\"\r
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\n" ); document.write( "\n" ); document.write( "go to \"W=L%2F2\", substitute\"+L\"\r
\n" ); document.write( "\n" ); document.write( "\"W=8ft%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"W=4ft\"\r
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\n" ); document.write( "\n" ); document.write( "so, the length \"L=8ft\" and width \"W=4ft\"\r
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\n" ); document.write( "\n" ); document.write( " the area is:\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"A=8ft%2A4ft\"\r
\n" ); document.write( "\n" ); document.write( "\"A=32ft%5E2\"\r
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