document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1206469>Question 1206469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> line with a slope of -3 passing through (4,-5)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #843979 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=843979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  line with a slope of -3 passing through (4,-5)<BR>\n" );
document.write( "Using the point/slope formula y - y1 = M(x - x10<BR>\n" );
document.write( "Substituting<BR>\n" );
document.write( "y - (-5) = -3(x - 4)<BR>\n" );
document.write( "y + 5 = -3x + 12<BR>\n" );
document.write( "y = -3x + 12 -5<BR>\n" );
document.write( "y = -3x + 7  is the line passing thru 4, -5) </SPAN>\n" );
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